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 Question from Kaitlyn, a student: how do you solve 2sin(2(theta))+sqrt(3)=0 with the interval [0,2pi)

Hi Kaitlyn,

Rewrite the equation as

$\sin(2 \theta) = - \frac{\sqrt {3}}{2}$

From this I know there are 2 solutions, one in the third quadrant and one in the fourth.

Can you solve it from here? Write back of you need more assistance.

Penny

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