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| Math Central | Quandaries & Queries |
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Question from Kaitlyn, a student: how do you solve 2sin(2(theta))+sqrt(3)=0 with the interval [0,2pi) |
Hi Kaitlyn,
Rewrite the equation as
\[\sin(2 \theta) = - \frac{\sqrt {3}}{2}\]
From this I know there are 2 solutions, one in the third quadrant and one in the fourth.
Can you solve it from here? Write back of you need more assistance.
Penny
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