



 
Mark, In the archives there is a schedule where 16 golfers play with each other exactly once over 5 rounds. (Search the archives for golf 16.) One way to go is to repeat it three times. For a bit of variety (to mix up the foursomes), you could use the schedule once, renumber the players and then use it again, and then renumber yet again and use the schedule over. It is also possible to change the day order within the 5round schedule and not hurt anything. Have fun! Mark responded
Mark, Maybe I still don't understand. Is it that each player in a foursome has exactly one opponent in that foursome? Or is it that every pair of players is together in a foursome exactly once? Or something else? The second outcome is impossible. The best that can be done is that every pair are together exactly three times. After 5 rounds, if no pair are together twice, each player has played with 3 x 5 = 15 others. The first outcome is possible with the schedule that was suggested. If the foursome is a, b, c, d, then the first time they are together a plays b and c plays d, the second time a plays c and b plays d, and the last time a plays d and b plays c. If neither of these is what you mean, please let try again and I will try to help. Victoria  


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