



 
Hi Samantha, Logarithms will help. The property of logarithms that is helpful here is that \[\log(a^b) = b \log(a).\] Thus if you have, for example \[6 = 1.34^x\] you can take the logarithm of both sides and the equation becomes \[\log(6) = \log\left((1.34^x\right) = x \log(1.34)\] and hence \[x = \frac{\log(6)}{\log{(1.34)}} = \frac{0.7782}{0.1271} = 6.12.\] Now try this with $4 = 1.08^x$. Penny  


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