Math CentralQuandaries & Queries


Question from sonit, a student:

the slope of tangent to the curve y=(4-x^2)^1/2 at the point, where the ordinate and abscissa are equal, is

Hi Sonit,

I expect you difficulty with this problem is the requirement that "the ordinate and abscissa are equal". The ordinate is the x-value and the abscissa is the y-value so yo fond the point or points where they are equal set $y = x$ in the equation to get $x=(4-x^2)^{1/2},$ square both sides and solve for $x.$ Check to see that for any value of $x$ you found that $x=(4-x^2)^{1/2}.$

Now find the slope of the tangent to the curve at these point(s).


About Math Central


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.
Quandaries & Queries page Home page University of Regina PIMS