



 
Hi Stephanie, Suppose that the length of the rectangle is $L$ meters and its width is $W$ meters, then its area is $L \times W$ square meters. Thus $L \times W = 88 m^{2}.$ Now use the fact that "the length of a rectangle is 5m more than twice its width". What is twice the width? What is 5 m more than that? This is the length so substitute this for $L$ in the equation above and solve for $W.$ Penny  


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