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 Hi Steve, The shape of each pile is approximately a cone and you can use the expression for the volume of a cone to find its volume. We have done precisely that in our response to an earlier question. There is however an easier procedure. The volume of a cone of radius $r$ units and height $h$ units is \[\pi \; r^2 h \mbox{ cubic units.}\] The volume of a cylinder with the same radius and height is \[\frac13 \pi\; r^2 h \mbox{ cubic units.}\] Hence the volume of the cone is one third the volume of the cylinder. My suggestion is that for each of your plies you use our volume calculator at mathcentral.uregina.ca/volume_calculator to calculate the volume of the cylinder with the dimensions you supplied and then divide by 3 to find the volume of the conical pile. You can use the example in the first paragraph of my response to check that you are using the procedure correctly. Harley  | ||||||||||||
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