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Hi, If the minimum degree of G is also k, then G is itself k-regular. Otherwise, make two copies G', G'' of G, and for every vertex u of G of degree less than k, join its copy u' in G' to its copy u'' in G''. Prove that the resulting graph is bipartite, and that its minimum degree is one more than that of G. Do you see how that helps? Claude | ||||||||||||
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