



 
Hi Varsha, This question has not got an answer! If the discs are placed at the corners of a square, you can see that the area between them is the However, the discs can be put at the corners of a rhombus, which has a smaller area (anywhere between 1 and $\large \frac{sqr{3}}{2} \normalsize \approx 0.87$ times that of the square, depending on its shape). As you can see, the missing sectors still add to exactly one disc. Good Hunting!
 


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