



 
Hi Walter, You have the equation $(4w28)+(11w+13)=180$ and you want to find a sequence of equivalent equations that ends with $w = \mbox{ something.} First of all you can remove the parentheses on the left side of the equation so that it becomes \[4w28+11w+13=180.\] Gathering the terms containing $w$ gives $4w+11w=15w.$ Also on the left you have $28+13=15$ so the equation becomes \[15w15=180.\] You only want terms involving $w$ on the left side so add 15 to each side to obtain \[15w15+15=180+15\] and hence \[15w=195.\] Finally multiply each side by $\frac{1}{15}$ to get \[\frac{1}{15}\times 15w=\frac{1}{15}\times195\] or \[w = 13.\] Penny  


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