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 Question from walter, a parent: i'm a parent helping my daughter can you do a step by step on this equation been out of school for years thanks (4w-28)+(11w+13)=180 thanks

Hi Walter,

You have the equation $(4w-28)+(11w+13)=180$ and you want to find a sequence of equivalent equations that ends with $w = \mbox{ something.} First of all you can remove the parentheses on the left side of the equation so that it becomes $4w-28+11w+13=180.$ Gathering the terms containing$w$gives$4w+11w=15w.$Also on the left you have$-28+13=-15$so the equation becomes $15w-15=180.$ You only want terms involving$w$on the left side so add 15 to each side to obtain $15w-15+15=180+15$ and hence $15w=195.$ Finally multiply each side by$\frac{1}{15}\$ to get

$\frac{1}{15}\times 15w=\frac{1}{15}\times195$

or

$w = 13.$

Penny

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