



 
Hi Yasmin, You didn't send any instructions but I assume you are to solve for $x.$ I can't solve algebraically so the best I can do is an approximation. I would use Newton's method. First write \[f(x) = \sin x  \log x  x^2\] and then use Newton's method as described in a response to an earlier question. I did a quick sketch of $\sin x$ and $\log x$ and decides that $x = 2$ is probably a reasonable initial value, $x_o.$ Harley  


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