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 Question from yasmin, a student: Sinx=logx+x^2

Hi Yasmin,

You didn't send any instructions but I assume you are to solve for $x.$ I can't solve algebraically so the best I can do is an approximation. I would use Newton's method.

First write

$f(x) = \sin x - \log x - x^2$

and then use Newton's method as described in a response to an earlier question. I did a quick sketch of $\sin x$ and $\log x$ and decides that $x = 2$ is probably a reasonable initial value, $x_o.$

Harley

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