



 
Hi Cherrielyn, I drew a circle of radius $r$ feet and an arc $A,$ subtended by an angle of $t^o$ at the center of the circle. The circumference of the circle is $2 \pi \; r$ feet. The length of the arc $A$ is a fraction of the circumference and the angle of measure $t^o$ is a fraction of $360^o .$ By the symmetry of the circle you can see that the fractions are the same. For example if $t = 180$ then $t$ is half of $360$ and $A$ is half of the circumference. That is \[A = \frac{180}{360} \times 2 \pi \; r = \frac{1}{2} \times 2 \pi \; r = \pi \; r.\] Likewise if $t = 90$ then \[A = \frac{90}{360} \times 2 \pi \; r = \frac{1}{4} \times 2 \pi \; r = \frac12 \pi \; r.\] The same relationship is true regardless of the value of $t.$ That is in general \[A = \frac{t}{360} \times 2 \pi \; r = \frac{t}{180} \times \pi \; r.\] Your railroad track is made up of two arcs. Find the length of each arc and add them to determine the length of the track. Penny  


Math Central is supported by the University of Regina and the Imperial Oil Foundation. 