



 
Hi Claire, If the Ferris wheel makes two revolutions in a minute it makes one revolution in 30 seconds and hence onethird of a revolution in 10 seconds. Onethird of $360^o$ is $120^o$ and in my diagram I have the Ferris wheel going clockwise so Sam is at the point Q after 10 seconds The measure of the angle $ROQ$ is $120^o  90^o = 30^o$. What is the length of $RQ?$ Subtract that from 85 feet to obtain Sam's height above the ground. Penny  


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