



 
Evan, It turns out that there is a schedule whereby every 2 players are in the same foursome exactly three times. It is pasted below. The 8 players are the positions in the sequence, and the numbers indicate the two foursomes (numbered 0 and 1 for convenience only). For example, on Day 0 the foursomes are 1, 2, 3, 4; 5, 6, 7, 8; and on Day 1 they are 1, 2, 5, 6; and 3, 4, 7, 8.
Another answer can be found here: http://mathcentral.uregina.ca/QQ/database/QQ.09.13/h/brian1.html —Victoria  


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