



 
Hi Joshua, 112  98 = 14 and 98  84 = 14 so the common difference for this arithmetic progression is 14. The first term is 112, the $2^{nd}$ term is 112 minus 14, the $3^{rd}$ term is 112 minus 2 times 14, the $4^{th}$ term is 112 minus 3 times 14, and so on. How many times do you subtract 14 to arrive at the $50^{th}$ term? What is the $50^{th}$ term? To calculate the sum look at my response to a question from Tim. Penny  


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