



 
Judi, You can’t get exactly what you want. Some pairs of players will need to be together three times, I think. There is a schedule for 16 players where every pair is together exactly once over 5 rounds. You can find it by searching for “golf 16” in the archives. If you delete players 15 and 16 wherever they occur, then you have a schedule for 5 rounds where every pair is together once. For one of the rounds you have 3 foursomes and a twosome, and for the other 4 you have 2 foursomes and 2 threesomes. For the first 10 weeks, use that schedule twice. The first time through it, add a player from the second threesome to the first threesome to get 3 fours and a two. The second time through, add a player from the first threesome to the second one. This schedule is pretty good. Most pairs are together twice, a few are together once. Schedule the last 2 weeks however you want; reusing week 1 and week 7 from the schedule for the first 10 weeks is not a terrible thing to do. —Victoria Judi wrote back
Judi, With that plan every pair have been in the same group once over 5 weeks. It seems like that's not what you want (sorry for the misunderstanding): instead you want each pair to play a match together. Try this. Number the players 1 to 13 and X. First form the matches
To get each subsequent week, add 1 to all player numbers from the current week using two rules for special cases: 13 + 1 = 1 (wrap around like an odometer), and X + 1 = X. This will give you the matches you want: every pair plays exactly one match together. Now you want to form the foursomes. I don't have a good way of doing that to balance the number of times every two players are in a group together. For each week you might just put the severn matches together in a hat and form the groups by random draw. Hope this helps.  


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