



 
Hi Lexie, $y = 0$ when $x = \pm 2$ and $x = 2$ is in the interval $5 \leq x \leq0$ and hence I needed to see a graph of the function. Here is my graph and you can see that for $5 \leq x \leq 2$ the graph is above the Xaxis and for $2 \leq x \leq 0$ the graph is below the Xaxis. Thus if you integrate $y = x^2  4$ from 5 to 2 you will get the area I shaded orange in the diagram. If you integrate $y = x^2  4$ from 2 to 0 you will get minus the area I shaded blue. Thus the area you want is the integral of $y = x^2  4$ from 5 to 2 MINUS the integral of $y = x^2  4$ from 2 to 0. Write back if you have trouble finishing the problem. Penny  


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