



 
Hi London, She has more dimes than nickels and more quarters than nickels so I would let $n$ be the number of nickels she has and work from there. She has twice as many dimes as nickels so she has $2n$ dimes. She has 4 more quarters than nickels so she has $n + 4$ quarters. To complete the problem you need to consider the value of the coins she has. Since we are dealing with nickels, dimes and quarter I would convert the total amount she has to cents and say she has 450 cents. Each nickel is worth 5 cents so the amount she has in nickels is $5 \times n$ cents. What is the amount she has in dimes? What is the amount she has in quarters? The total is 450 cents. Solve for $n.$ Penny  


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 