Math CentralQuandaries & Queries


Question from Maree:

We are taking 18 golfers on Tour with a teaching Pro. There are 5 rounds of golf and we want everyone to play with the Pro once, but everyone else to play with as many different people as possible


If you play in foursomes, then 3 people get to play with the pro each round. That's a total of 15 out of your 18. So what you want is not possible.

Look at this answer and delete golfer 20: In this schedule, the players that don't play together are the ones the the same column. So, if the pro is one of player 4, 8, 12, 16 (and it does not matter which one), then the schedule you get is the best one possible. No two players are together twice.


About Math Central
* Registered trade mark of Imperial Oil Limited. Used under license.


Math Central is supported by the University of Regina and the Imperial Oil Foundation.
Quandaries & Queries page Home page University of Regina Imperial Oil Foundation