



 
Hi Pearl, You know the limit of $\large \frac{\sin(t)}{t}$ as $t$ goes to 0 and the limit of $\large \frac{\cos(t)}{t}$ as $t$ goes to zero. For your expression \[\frac{\sin(8x)}{\cos(6x)}\] first write the numerator as \[\sin(8x) = 8x \times \frac{\sin(8x)}{8x}.\] Now do something similar for $\cos(6x).$ Put your original fraction \[\frac{\sin(8x)}{\cos(6x)}\] back together and simplify. Penny  


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