 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Question from pearl, a student: (what is the value of limit of x as it approaches 0 of sin8x divided by cos6x) |
Hi Pearl,
You know the limit of $\large \frac{\sin(t)}{t}$ as $t$ goes to 0 and the limit of $\large \frac{\cos(t)}{t}$ as $t$ goes to zero. For your expression
\[\frac{\sin(8x)}{\cos(6x)}\]
first write the numerator as
\[\sin(8x) = 8x \times \frac{\sin(8x)}{8x}.\]
Now do something similar for $\cos(6x).$ Put your original fraction
\[\frac{\sin(8x)}{\cos(6x)}\]
back together and simplify.
Penny
| ||
| ||
| ||
 |
 |
|
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.