



 
Hi Sindy, Both problems you sent us I would call "working backwards" problems. For this problem I see 4 steps.
At step 4 he counted his money and he had $\$60.$ At step 3 he bought a pair of jeans for $\$60$ and what he had left was $\$60$ so at step 3 he had $\$120.$
At step 2 he bought a wallet with 1/5 of the money he had at this point. He was left with $\$120$ so 4/5 of the money he had at this point was $\$120.$ Since $\large \frac{120}{4} \normalsize = 30$ he spent $\$30$ on the wallet. Thus, before he bought the wallet he had $\$120 + \$30 = \$150.$
How much did he have before he bought the shoes? Check your answer by working forward. Now try the second problem you sent us. Penny  


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