



 
Hi Srishti, Suppose $(x, y)$ is a point on the locus then its distance from the origin is $\sqrt{x^2 + y^2}.$ Suppose that $y \geq 0$ then the distance from $(x, y)$ to the Xaxis is $y$ and hence for $(x, y)$ to be on the locus you must have \[\sqrt{x^2 + y^2}  y = c.\] Simplify and solve for $y.$ Now suppose that $y < 0$ then the distance from $(x, y)$ to the Xaxis is $y.$ Write an expression analogous to the expression above, simplify and solve for $y.$ Thus the locus of $(x, y)$ is given in two parts, one for $y \geq 0$ and the other for $y < 0.$ Penny  


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