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| Math Central | Quandaries & Queries |
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Question from Thomas, a parent: I'm trying to help my 9th grade child with their homework. The problem is the |
Hi Thomas,
Suppose the length of the rectangle is $L$ m and the width is $W$ m.
You know two facts that you want to use to produce two equations in $L$ and $W.$
First the length is twice the width so $L = 2 W.$
The second fact is that the perimeter is 68 m. The perimeter is $L + W + L + W$ so your second equation is $2L + 2W = 68.$
From the first equation you can substitute $L = 2 W$ into the second equation and solve for $W.$
I hope this helps,
Penny
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