 |
| ||
| |||
|
| Math Central | Quandaries & Queries |
|
Question from Bella, a student: The directions are the solve and factor the expression completely: I was factoring out an (x+1) and and (x-3) however the answer showing in my book is different and I can't figure out what I'm doing wrong please help |
Hi Bella,
When I factored out the two common factors I got
\[2(x+1)(x-3)^2-3(x+1)^2(x-3) = (x + 1)(x - 3)\left[2(x - 3) - 3(x + 1)\right]\]
You then need to simplify what is inside the square brackets.
Is that what you got?
Penny
| ||
| ||
| ||
 |
 |
|
|
||
Math Central is supported by the University of Regina and the Imperial Oil Foundation.