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 Question from Bella, a student: The directions are the solve and factor the expression completely: 2(x+1)(x-3)^2-3(x+1)^2(x-3) I was factoring out an (x+1) and and (x-3) however the answer showing in my book is different and I can't figure out what I'm doing wrong please help

Hi Bella,

When I factored out the two common factors I got

$2(x+1)(x-3)^2-3(x+1)^2(x-3) = (x + 1)(x - 3)\left[2(x - 3) - 3(x + 1)\right]$

You then need to simplify what is inside the square brackets.

Is that what you got?
Penny

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