|
|||||||||||||||
|
|||||||||||||||
| |||||||||||||||
Hi Kevin, I am going to change the name of the second expression so it is clear which one I am referring to. The first expression is $y = f(x)$ and the second is $z = \frac{-3}{2} f(x).$ The second expression multiplies each value of the first expression by the fraction $\frac{-3}{2}.$ Thus if $(3,4)$ is a point that satisfies the first expression $y = f(x)$ (that is $f(3) = 4)$ then the corresponding point that satisfies $z = \frac{-3}{2} f(x)$ is $(3, \frac{-3}{2} \times 4) = (3, -6).$ Thus, if you have a point on the graph of the $y$ expression then the corresponding point on the graph of the $z$ expression has the same first coordinate but the second coordinate is $\frac{-3}{2}$ times the second coordinate of the point on the graph of the $y$ expression. I hope this helps, | |||||||||||||||
|
|||||||||||||||
Math Central is supported by the University of Regina and the Imperial Oil Foundation. |