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 Math Central Quandaries & Queries

Hi Margot,

You are almost done. You have the derivative of $V(h)$ and you have set it equal to zero.

$12h^2 - 8zh + z^2 = 0.$

$(6h - z)(2h - z) = 0$
and thus $h = \frac{z}{6}$ or $h = \frac{z}{2}.$ The first gives you what you discovered in part 7. What about the second?