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| Math Central | Quandaries & Queries |
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Question from martin: I have to organize 14 players to play four rounds of golf. Each round comprise two fourballs and two three balls . What's the best combination to ensure that each persons plays with as many of the others as possible without playing with somebody more than twice? |
Martin,
Start with a schedule for 16 players, say this one http://mathcentral.uregina.ca/QQ/database/QQ.09.08/h/bill4.html. Delete two players. It does not matter which two. Use the four days that are comprised of two threesomes and two foursomes (the fifth day has a twosome and three foursomes). Every pair of players plays together at most once. The players that are not ever together are the ones who would be together on the fifth day. This schedule is the best possible.
Hope this makes sense.
—Victoria
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