   SEARCH HOME Math Central Quandaries & Queries  Question from Mubashir, a student: A,B,C,D are the four corners of a rectangular plot marked on level ground. Given that the bearing of B from A is 040 degrees and that the bearing of C from A is 090 degrees. Calculate the bearing of (a)B from C (b)A from C (c) D from C Ho Mubashir,

The bearing from $B$ to A is the angle between the line segment $BA$ and north, measuring clockwise. The bearing from $C$ to $A$ is 90 degrees and again the bearing is measured clockwise from north and thus $C$ must be on the east-west ray $L_1$ in the diagram below. From the diagram the measure of the angle $BAC$ is 60 degrees and hence $AC$ is not a side of the rectangle. Hence the angle measure of the angle $CBA$ is 90 degrees. Draw a line through $B$ which is perpendicular to $BA$ and this line must intersect the line $L_1$ at $C.$ Finally draw a line through $C$ parallel to $BA$ and a line through $A$ parallel to $BC.$ These lines meet at $D$ the last corner of the rectangular plot. From the diagram you should now be able to determine the bearings required.

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