



 
Hi Najah, I am going to assume your equation is \[\left( m^2  1\right) x^2  (m + 3) x + 4  m^2 = 0.\] A quadratic equation in the variable $x$ is an equation of the form $a x^2 + b x + c = 0$ where $a, b$ and $c$ are constants and $a \neq 0.$ Thus your equation is a quadratic as long as $m^2  1 \neq 0.$ For B part, if $1$ is a root then substituting $x = 1$ into the equation yields $0.$ Solve for $m.$ Penny  


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