



 
Hi Omar, For each $x$ calculate the value of $P(X = x),$ for example \[P(X = 2) = k \times 2^3 = 8k.\] Use the fact that \[P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 1\] and solve for $k.$ Penny  


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