



 
Hi, Your auto cad drawing didn't arrive but I drew a much smaller situation, similar to what you described. In my situation the diameter of the circle is 4.42 m and the spacing between the rods is 0.5 m. Consider the vertical rods in my drawing. The diameter of the circle is 4.21 m and the spacing between the rods in 0.5 m and $\large \frac{4.21}{0.5} \normalsize = 8.41$ strips. Hence there are 8 strips of width 0.5 m each and a width of 0.41 m which is evenly divided into narrow strips on each side. Thus the rods partition the circle onto 10 strips which requires 9 rods. I hope this helps, Penny
 


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