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 Question from seyilogo, a student: solve y=2x - 3 and (4x - 2y) / x + y = 1 simultaneously

Hi Seyilogo,

I would use the first equation $y = 2x - 3$ and use it to substitute for $y$ in the second equation

$\frac{4x - 2y}{x} + y = 1$

to yield an equation in $x$ alone. Simplify and solve for $x.$

Harley

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