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| Math Central | Quandaries & Queries |
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Question from seyilogo, a student: solve y=2x - 3 and (4x - 2y) / x + y = 1 simultaneously |
Hi Seyilogo,
I would use the first equation $y = 2x - 3$ and use it to substitute for $y$ in the second equation
\[\frac{4x - 2y}{x} + y = 1\]
to yield an equation in $x$ alone. Simplify and solve for $x.$
Harley
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