



 
Hi Aaron, It's surprising how many times Pythagoras Theorem is helpful. Triangle $ABC$ is a right triangle and hence Pythagoras Theorem tells us that \[AB^2 + BC^2 = CA^2\] or \[CA^2 = 27^2 + 20^2 = 1129\] so \[CA = \sqrt{1129} = 33.6 \mbox{ inches.}\] Thus it will fit but it is tight. Each corner of the puzzle will only be 1.8 inches from the circle. Penny  


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