



 
Hi Astri, I am not sure what you are looking for. The questions we have received for a horizontal tank ask for the volume of liquid in the tank when the height of the liquid is given. For example this is the question that Dave asked a while ago. If you want the volume of liquid in a tilted cylindrical tank as indicated in the diagram below then the volume $V$ is given by \[V = \pi r^2 \times \frac{h_1 + h_2}{2} \mbox{ cubic units}\] where $h_1$ and $h_2$ are the shortest and longest measurements from the bottom to the top respectively. I assume that you know $h_2$ and the angle $\theta$ in degrees. If so then you can find $h_1$ by \[h_1 = h_2  2r \tan \theta .\] I hope this helps,  


Math Central is supported by the University of Regina and the Imperial Oil Foundation. 