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Hi Bryan, Suppose you had a square and each side measures 5 units. The area of thus square is then $5 \times 5 = 25$ square units. Now perform the same operation when each side is of length $4x-3$ units. For my square I expanded $5 \times 5$ to get $25.$ What do you get when you expand the area expression for a square with sides of length $4x-3$ units? Penny | |||||||||||||||
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