



 
Hi Edwin, I expect it is the fractions in the expression \[\frac13 (x  5) = \frac16 (2  3x) + 1\] that is the problem, so let's eliminate them. If you multiply the left side by 3 then the fraction there is eliminated but if you multiply the right side by 3 you still have a fraction of $\large \frac{1}{2}.$ If you multiply both sides by 6 you eliminate both fractions. My suggestion then is that you multiply both sides by 6 and solve the resulting equation for $x.$ Make sure you verify your answer. Write back if you need more assistance,  


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