



 
i Jack, I drew a diagram of your truncated cone and drew a line from $B$ to intersect the base at $C.$ The length of the line segment $BC$ is $h,$ the height in inches. Since the radius of the top is $15$ inches and the radius of the base is $32$ inches the length of the line segment $CA$ is $32  15 = 17$ inches and the measure of the angle $CAB$ is $65^{o}.$ Thus \[\tan\left(65^o\right) = \frac{h}{CA}\] or \[h = 17 \times \tan\left(65^o\right) \mbox{ inches.}\] Penny  


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