



 
Hi Kirby, In my diagram $S$ is the initial position of the ship, $T$ is its position after it has travelled 2250 feet, $L$ is the position of the light and $N$ is the closest point to $L$ on the path being followed by the ship. The angle $LNS$ is a right angle. Bearing is measured clockwise from north so in my diagram the angle $NSL$ has measure $297^0 50^'  270^{o}.$ What is the measure of the angle $NTL?$ Use trigonometry and the right triangles $LNT$ and $LNS$ to find two equations in the variables $x$ and $d.$ Solve for $d.$ Penny  


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