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| Math Central | Quandaries & Queries |
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Question from Mike: We are six golfers going away for 3 days of golf. We are playing in 2 no threeballs playing concurrently. How can we arrange things so that everyone plays everybody else at least once. Is this possible.? |
Mike,
It isn't. After day 1 each threesome will contain at least 1 group of players who have played together before. That does not leave enough “room” to cover all 15 possible pairs from among 6 players. The best schedule I could find by hand or computer covered 12 of the 15 pairs. It is 1, 2, 3 and 4, 5, 6; then 1, 2, 4 and 3, 5, 6; then 1, 3, 5 and 2, 4, 6.
—Victoria
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