|
|||||||||||||||
|
|||||||||||||||
| |||||||||||||||
Hi, In my diagram $PQR$ is the isosceles triangle, C is the centre of the circle. Angle $QSP$ is a right angle. Can you see why? Use the fact that triangle $QSP$ to find the length $|QS|.$ Suppose that $r$ is the radius of the circle and $|SC| = x.$ Use the fact that $|QC| = r = |QS| + |SC|$ and the fact that triangle $PSC$ is a right triangle to find $r.$ Penny | |||||||||||||||
|
|||||||||||||||
Math Central is supported by the University of Regina and the Imperial Oil Foundation. |