



 
Pearl, are you sure you have worded this properly? Should it say the Penny Pearl wrote back
Pearl, Look at Walter's response to Evelina about the exterior angles of a regular polygon. He gives a geometric argument to show that the exterior angles of a regular polygon with $n$ sides each measure $\large \frac{360}{n}$ degrees. Hence each interior angle measures $180  \large \frac{360}{n}$ degrees. If each exterior angle is 8 times an interior angle then \[\frac{360}{n} = 8 \times \left( 180  \frac{360}{n} \right ).\] Solve for $n.$ The problem I have is that $n$ is not an integer. That is why I asked you if you had worded the problem correctly. If the internal angle is 8 times the external angle then $n$ is an integer. I hoe this helps,  


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