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 Question from sahil, a student: Find the equation of diameter of circle x^2 +y^2-6x +2y-8 = 0 which passes through the origin.

Hi Sahil,

You need to find the equation of the line through $(0, 0)$ and the center of the circle. To find the center of the circle you need to complete the square of the $x$ terms and the $y$ terms in the equation you sent.

Write back if you need more assistance,
Penny

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