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| Math Central | Quandaries & Queries |
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Question from Ting, a student: The first four terms of a sequence are 4, 20, 56 and 120. By comparing with the nth term of sequence 1,5,14 and 30 which is 1/6n(n+1)(2n+1), find a formula for nth term. Can you precisely show out how you do this questions ( with the steps please) |
Hi Ting,
The two sequences begin
\begin{eqnarray*}
1 & 5& &14& & 30&\\
4 &20& &56& &120&
\end{eqnarray*}
How does each term of the second sequence relate to the corresponding term of the first sequence?
Penny
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