



 
Hi, Suppose the square measures $X$ m on each side and the rectangle $W$ m wide and $L$ m long. Since the length of the rectangle is twice the width $L = 2 W.$ Hence the total area enclosed $A$ is given by \[ A = x^2 + L \times W = X^2 + (2W) \times W = X^2 + 2W^2 \mbox{ square metres.}\] The task is to use the calculus you know to maximize the expression for $A$ but $A$ is a function of two variables $X$ and $W.$ Use the fact that the length of fencing used is 300 m to express $A$ as a function of one variable and then use your calculus knowledge. Write back if you need more assistance,  


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