Hi Babawale,

I would start by adding $342_5$ and $132_5$ in base 5.

Starting at the units column two plus two is four so I get

Now the fives column, four plus three is seven and seven in base 5 is $12_5$ so I write the 2 and carry the 1

Finally in the twenty-fives column three plus one plus one is five which in base 5 is $10_5$ and hence

Now your problem reduces to

\[1024_5 - 223_{5}.\]

For that you should look at our response to an earlier question.

Penny