



 
Hi Brian, At the start there are 12 eggs in the basket, 6 hardboiled and 6 uncooked so the probability that the first egg selected is hardboiled is $\frac{6}{12}.$ Now there are 11 eggs in the basket, 5 hardboiled and 6 uncooked so the probability that the second egg selected is uncooked given that the first egg was hardboiled is $\frac{6}{11}.$ Thus the probability that the first egg selected is hardboiled AND the second egg selected is uncooked given that the first egg was hardboiled is $\frac{6}{12} \times \frac{6}{11}.$ The pattern continues, the probability that the third egg selected is hardboiled given that first egg selected is hardboiled AND the second egg selected is uncooked given that the first egg was hardboiled is $ \frac{6}{12} \times \frac{6}{11} \times \frac{5}{10}.$ Continue for 8 eggs. Penny  


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