



 
Hi Jeff, I drew a diagram. Since the area of the smaller square is 1 square unit each of its sides has length 1 unit. $C$ is the centre of the circle and hence $CA = AB = \frac12$ units. Use Pythagoras' Theorem to find the length of $CB.$ Since $CB$ and $CD$ are both radii of the circle $CD = CB.$ But $CD$ is half the length of a side of the larges square? What is the length of a side of the larger square? What is its area? I was surprised by the answer,  


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