



 
Hi Kathy, You didn't give any instructions. Are you to solve for $x?$ If so then the best you can do is approximate a solution. I am going to let \[L(x) =2^x \mbox{ and } R(x) = 2x11\] and then you are looking for the value of $x$ so that $L(x) = R(x).$ I made a quick sketch of $y = L(x)$ and $y = R(x)$ on the same graph and this was he result and you can see that where the line $y = R(x)$ crosses the xaxis it is very close to intersecting the curve $y = L(x).$ $R(5.5) = 0$ and hence the line $y = R(x)$ crosses the xaxis at $(5.5,0).$ Also $L(5.5) = 2^5.5 = 0.0221$ and hence when $x = 5.5$ the expressions $2^x \mbox{ and } 2x  11$ are almost equal. From the graph you can see that the point where the curves intersect is a little to the left of $x = 5.5$ and hence if you want a better approximation you can try a value of $x$ a little less than 5.5. If this is for a calculus class you can use the Newton Raphson method to obtain an approximate solution. I hope this helps,  


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