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 Question from Nilesh, a student: How to solve (x-y)^1/2 + 3(x-y) = 30 ; xy + 3(x-y) = 11 ? .

Hi Nilesh,

I can help get you started.

Focus on the first equation

$(x-y)^{1/2} + 3(x-y) = 30$

and let

$z = (x-y)^{1/2}.$

Once you have found $x$ and $y$ make sure you verify your answer.

Penny

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