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Hi Atina, I can help get you started. On any two-spins of the spinner you can obtain 1 to 4 as the first (tens) digit and 1 to 4 as the second (units) digit. Thus you resulting two-digit number can be any one of 11, 12, 13, 14, 21, ... 24, 31,..., 41, ... 44 This is the sample space and contains 16 elements. Since any single spin yields 1 to 4, equally likely, any of the 16 possible outcomes in the sample space are equally likely. For the first bullet in part (c) you want outcomes that are not in $E$ but are in $F.$ The sample space is $S$ so I would write the elements not in $E$ as $S - E.$ Your textbook or teacher may use some other notation. So for this bullet you want the outcomes in $S - E$ and in $F.$ This is the intersection of $S - E$ and $F$ which I would write $(S - E) \cap F.$ Penny | |||||||||||||||||||||
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