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Hi Dan, If you have a problem of the form \[a^n = b\] and you are to solve for $n,$ the standard technique is to take the log of both sides to get \[log\left(a^n\right) = log(b) \mbox{ or }n \times log(a) = log(b).\] Now solve for $n.$ Penny | |||||||||||||||||||||
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Math Central is supported by the University of Regina and the Imperial Oil Foundation. |